Answers:
1. Answer:
30
days.
Explanation:
Before:
One day work = 1
/ 20
One man’s one day work = 1
/ ( 20 * 75)
Now:
No.
Of workers = 50
One
day work = 50 * 1 / ( 20 * 75)
The
total no. of days required to complete the work = (75 * 20) / 50 = 30
2. Answer:
0
%
Explanation:
Since 3x / 2 = x / (2 / 3)
3. Answer:
5.3 %
Explanation:
He
sells 950 grams of pulses and gains 50 grams.
If he sells 100 grams of pulses then
he will gain (50 / 950) *100 = 5.26
4. Answer:
250
lines of codes
5. Answer:
7
days
Explanation:
The
equation portraying the given problem is:
10 * x
– 2 * (30 – x) = 216 where x is the number of working days.
Solving
this we get x = 23
Number
of days he was absent was 7 (30-23) days.
6. Answer:
150
men.
Explanation:
One
day’s work = 2 / (7 * 90)
One
hour’s work = 2 / (7 * 90 * 8)
One
man’s work = 2 / (7 * 90 * 8 * 75)
The
remaining work (5/7) has to be completed within 60 days, because the total
number of days allotted for the project is 150 days.
So
we get the equation
(2 * 10 * x * 60) / (7 *
90 * 8 * 75) = 5/7 where x is the number of men working after
the 90th day.
We get x = 225
Since we have 75 men already, it is
enough to add only 150 men.
7. Answer:
(c)
1
Explanation:
a
percent of b : (a/100) * b
b percent of a : (b/100) * a
a percent of b divided by b percent
of a : ((a / 100 )*b) / (b/100) * a )) =
1
8. Answer:
Cost
price of horse = Rs. 400 & the cost
price of cart = 200.
Explanation:-
Let x be the cost price of the horse
and y be the cost price of the cart.
In the first sale there is no loss
or profit. (i.e.) The loss obtained is equal to the gain.
Therefore (10/100) * x = (20/100) * y
X =
2 * y -----------------(1)
In the second sale, he lost Rs. 10.
(i.e.) The loss is greater than the profit by Rs. 10.
Therefore (5 / 100) * x = (5 / 100) * y + 10
-------(2)
Substituting (1) in (2)
we get
(10 / 100) *
y =
(5 / 100) * y + 10
(5 / 100) *
y =
10
y = 200
From (1) 2 * 200
= x = 400
9. Answer:
3.
Explanation:
Since
inclusion of any male player will reject a female from the team. Since there
should be four member in the team and only three males are available, the girl,
n should included in the team always irrespective of others selection.
10. Answer:
5
11. Answer:
1,2,3
& 4
12. Answer:
B
13. Answer:
11
& 9 apples per tree.
Explanation:
Let a, b, c, d & e be the total
number of apples bored per year in A, B, C, D & E ‘s orchard. Given that a + 1 = b + 3 = c – 1 = d + 3 = e – 6
But the question
is to find the number of apples bored per tree in C and D ‘s orchard. If is
enough to consider c – 1 = d + 3.
Since the number of trees in C’s
orchard is 11 and that of D’s orchard is 13. Let x and y be the number of
apples bored per tree in C & d ‘s orchard respectively.
Therefore 11 x – 1 = 13 y + 3
By trial and
error method, we get the value for x and y as 11 and 9
14. Answer:
G.
Explanation:
The order in which
they are climbing is R – G – K – H – J
15 – 18
Answer:
Novel
Name Author Publisher
Spy thriller Rathko Heron
Murder
mystery Gorky Piegon
Gothic
romance Burchfield Blueja
Science
fiction Hopper Sparrow
Explanation:
Given
Novel
Name Author Publisher
Spy
thriller Rathko Heron
Murder
mystery Gorky Piegon
Gothic
romance Burchfield Blueja
Science
fiction Hopper Sparrow
Since
Blueja doesn’t publish the novel by Burchfield and Heron publishes the novel
spy thriller, Piegon publishes the novel by Burchfield.
Since
Hopper writes Gothic romance and Heron publishes the novel spy thriller, Blueja
publishes the novel by Hopper.
Since
Heron publishes the novel spy thriller and Heron publishes the novel by Gorky,
Gorky writes Spy thriller and Rathko writes Murder mystery.
19. Answer:
451
times.
Explanation:
There
are 60 minutes in an hour.
In ¾ of an hour there are (60 * ¾)
minutes = 45 minutes.
In
¾ of an hour there are (60 * 45) seconds = 2700 seconds.
Light flashed for every 6 seconds.
In 2700 seconds 2700/6 = 450 times.
The count start
after the first flash, the light will flashes 451 times in ¾ of an hour.
20. Answer:
(4)
Explanation:
P
A B
Since
p is a point on the line segment AB, AB > AP
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